Προβλημα με ARDUINO

[arduinowarrior]

Καλησπέρα, κατά την επικύρωση  προγράμματος στον compiler του arduino μου βγάζει "error compiling for board Arduino/Genuino uno.

Γνωρίζει κανεις τι μπορει να φταίει ?

Ευχαριστω!

Έγινε επεξεργασία Μάϊος 31, 2017 από arduinowarrior

[eleozz]

αμα θέλεις γράψε μας τον κώδικα που προσπαθεις να κάνεις compile, κατα πάσα πιθανότητα ιπάρχι καπιο μικρό λαθάκι

[arduinowarrior]

#include <Keypad.h>

const byte numRows= 4; //number of rows on the keypad
const byte numCols= 4; //number of columns on the keypad

//keymap defines the key pressed according to the row and columns just as appears on the keypad
char keymap[numRows][numCols]= 
{
{'1', '2', '3', 'A'}, 
{'4', '5', '6', 'B'}, 
{'7', '8', '9', 'C'},
{'*', '0', '#', 'D'}
};

//Code that shows the the keypad connections to the arduino terminals
byte rowPins[numRows] = {9,8,7,6}; //Rows 0 to 3
byte colPins[numCols]= {5,4,3,2}; //Columns 0 to 3

//initializes an instance of the Keypad class
Keypad myKeypad= Keypad(makeKeymap(keymap), rowPins, colPins, numRows, numCols);

void setup()
{
Serial.begin(9600);
}

//If key is pressed, this key is stored in 'keypressed' variable
//If key is not equal to 'NO_KEY', then this key is printed out
//if count=17, then count is reset back to 0 (this means no key is pressed during the whole keypad scan process
void loop()
{
char keypressed = myKeypad.getKey();
if (keypressed != NO_KEY)
{
Serial.print(keypressed);
}
}

[arduinowarrior]

το βρήκα! σε ευχαριστω πολυ παντως!